Rounding off decimal value in Groovy

I am new to groovy language, so assume its going to be bare basic.

By default you have an object defined in groovy like follows:

groovy> def number=12.11 
groovy> println number.round(2) 

Exception thrown

groovy.lang.MissingMethodException: No signature of method: java.math.BigDecimal.round() is applicable for argument types: (java.lang.Integer) values: [2]
Possible solutions: round(java.math.MathContext), find(), pow(int), and(java.lang.Number), power(java.lang.Integer), mod(java.lang.Number)

I was searching in google for identifying the issue, but could not resolve it. Later only I realized that round() is available in double in groovy. I then explicitly converted the variable to double using toDouble() method and chained the round() method to it. It solved my problem.

groovy> def number=12.11 

groovy> println number.getClass()

groovy> println number.toDoublt().getClass()

groovy> println number.toDouble().round(2) 

class java.lang.Double

class java.math.BigDecimal

12.11

So it is evident that the method round() is not available to BigDecimal whereas it is available to Double.

So how can I round off a BigDecimal? Waiting for the answer.

Categories: FAQ , Groovy